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-2(v+1)+5v=3(v+1)-5
We move all terms to the left:
-2(v+1)+5v-(3(v+1)-5)=0
We add all the numbers together, and all the variables
5v-2(v+1)-(3(v+1)-5)=0
We multiply parentheses
5v-2v-(3(v+1)-5)-2=0
We calculate terms in parentheses: -(3(v+1)-5), so:We add all the numbers together, and all the variables
3(v+1)-5
We multiply parentheses
3v+3-5
We add all the numbers together, and all the variables
3v-2
Back to the equation:
-(3v-2)
3v-(3v-2)-2=0
We get rid of parentheses
3v-3v+2-2=0
We add all the numbers together, and all the variables
=0
v=0/1
v=0
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