-2(v+2)-2=8-5(1+v)

Solution for -2(v+2)-2=8-5(1+v) equation:

-2(v+2)-2=8-5(1+v)

We move all terms to the left:

-2(v+2)-2-(8-5(1+v))=0

We add all the numbers together, and all the variables

-2(v+2)-(8-5(v+1))-2=0

We multiply parentheses

-2v-(8-5(v+1))-4-2=0


We calculate terms in parentheses: -(8-5(v+1)), so:

8-5(v+1)

determiningTheFunctionDomain
-5(v+1)+8

We multiply parentheses

-5v-5+8

We add all the numbers together, and all the variables

-5v+3

Back to the equation:

-(-5v+3)


We add all the numbers together, and all the variables

-2v-(-5v+3)-6=0

We get rid of parentheses

-2v+5v-3-6=0

We add all the numbers together, and all the variables

3v-9=0

We move all terms containing v to the left, all other terms to the right

3v=9

v=9/3

v=3