-2(v+2)-2=8-5(1+v)

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Solution for -2(v+2)-2=8-5(1+v) equation:



-2(v+2)-2=8-5(1+v)
We move all terms to the left:
-2(v+2)-2-(8-5(1+v))=0
We add all the numbers together, and all the variables
-2(v+2)-(8-5(v+1))-2=0
We multiply parentheses
-2v-(8-5(v+1))-4-2=0
We calculate terms in parentheses: -(8-5(v+1)), so:
8-5(v+1)
determiningTheFunctionDomain -5(v+1)+8
We multiply parentheses
-5v-5+8
We add all the numbers together, and all the variables
-5v+3
Back to the equation:
-(-5v+3)
We add all the numbers together, and all the variables
-2v-(-5v+3)-6=0
We get rid of parentheses
-2v+5v-3-6=0
We add all the numbers together, and all the variables
3v-9=0
We move all terms containing v to the left, all other terms to the right
3v=9
v=9/3
v=3

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