-2(v+2)=4v-6+2(3v+8)

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Solution for -2(v+2)=4v-6+2(3v+8) equation:



-2(v+2)=4v-6+2(3v+8)
We move all terms to the left:
-2(v+2)-(4v-6+2(3v+8))=0
We multiply parentheses
-2v-(4v-6+2(3v+8))-4=0
We calculate terms in parentheses: -(4v-6+2(3v+8)), so:
4v-6+2(3v+8)
determiningTheFunctionDomain 4v+2(3v+8)-6
We multiply parentheses
4v+6v+16-6
We add all the numbers together, and all the variables
10v+10
Back to the equation:
-(10v+10)
We get rid of parentheses
-2v-10v-10-4=0
We add all the numbers together, and all the variables
-12v-14=0
We move all terms containing v to the left, all other terms to the right
-12v=14
v=14/-12
v=-1+1/6

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