-2(v+2)=4v-6+2(3v+8)

Solution for -2(v+2)=4v-6+2(3v+8) equation:

-2(v+2)=4v-6+2(3v+8)

We move all terms to the left:

-2(v+2)-(4v-6+2(3v+8))=0

We multiply parentheses

-2v-(4v-6+2(3v+8))-4=0


We calculate terms in parentheses: -(4v-6+2(3v+8)), so:

4v-6+2(3v+8)

determiningTheFunctionDomain
4v+2(3v+8)-6

We multiply parentheses

4v+6v+16-6

We add all the numbers together, and all the variables

10v+10

Back to the equation:

-(10v+10)


We get rid of parentheses

-2v-10v-10-4=0

We add all the numbers together, and all the variables

-12v-14=0

We move all terms containing v to the left, all other terms to the right

-12v=14

v=14/-12

v=-1+1/6