-2(v+2)=v-9+5(3v+3)

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Solution for -2(v+2)=v-9+5(3v+3) equation: 



-2(v+2)=v-9+5(3v+3)

We move all terms to the left:

-2(v+2)-(v-9+5(3v+3))=0

We multiply parentheses

-2v-(v-9+5(3v+3))-4=0



We calculate terms in parentheses: -(v-9+5(3v+3)), so:

v-9+5(3v+3)

determiningTheFunctionDomain
v+5(3v+3)-9

We multiply parentheses

v+15v+15-9

We add all the numbers together, and all the variables

16v+6

Back to the equation:

-(16v+6)



We get rid of parentheses

-2v-16v-6-4=0

We add all the numbers together, and all the variables

-18v-10=0

We move all terms containing v to the left, all other terms to the right

-18v=10

v=10/-18

v=-5/9

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