-2(v+3)=4v-4+2(3v+2)

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Solution for -2(v+3)=4v-4+2(3v+2) equation: 



-2(v+3)=4v-4+2(3v+2)

We move all terms to the left:

-2(v+3)-(4v-4+2(3v+2))=0

We multiply parentheses

-2v-(4v-4+2(3v+2))-6=0



We calculate terms in parentheses: -(4v-4+2(3v+2)), so:

4v-4+2(3v+2)

determiningTheFunctionDomain
4v+2(3v+2)-4

We multiply parentheses

4v+6v+4-4

We add all the numbers together, and all the variables

10v

Back to the equation:

-(10v)



We add all the numbers together, and all the variables

-12v-6=0

We move all terms containing v to the left, all other terms to the right

-12v=6

v=6/-12

v=-1/2

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