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-2(v+5)=v-9+3(5v+1)
We move all terms to the left:
-2(v+5)-(v-9+3(5v+1))=0
We multiply parentheses
-2v-(v-9+3(5v+1))-10=0
We calculate terms in parentheses: -(v-9+3(5v+1)), so:We get rid of parentheses
v-9+3(5v+1)
determiningTheFunctionDomain v+3(5v+1)-9
We multiply parentheses
v+15v+3-9
We add all the numbers together, and all the variables
16v-6
Back to the equation:
-(16v-6)
-2v-16v+6-10=0
We add all the numbers together, and all the variables
-18v-4=0
We move all terms containing v to the left, all other terms to the right
-18v=4
v=4/-18
v=-2/9
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