-2(v+6)=v-1+3(5v+1)

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Solution for -2(v+6)=v-1+3(5v+1) equation: 



-2(v+6)=v-1+3(5v+1)

We move all terms to the left:

-2(v+6)-(v-1+3(5v+1))=0

We multiply parentheses

-2v-(v-1+3(5v+1))-12=0



We calculate terms in parentheses: -(v-1+3(5v+1)), so:

v-1+3(5v+1)

determiningTheFunctionDomain
v+3(5v+1)-1

We multiply parentheses

v+15v+3-1

We add all the numbers together, and all the variables

16v+2

Back to the equation:

-(16v+2)



We get rid of parentheses

-2v-16v-2-12=0

We add all the numbers together, and all the variables

-18v-14=0

We move all terms containing v to the left, all other terms to the right

-18v=14

v=14/-18

v=-7/9

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