-2(w+2)=2w-3+4(2w+2)

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Solution for -2(w+2)=2w-3+4(2w+2) equation: 



-2(w+2)=2w-3+4(2w+2)

We move all terms to the left:

-2(w+2)-(2w-3+4(2w+2))=0

We multiply parentheses

-2w-(2w-3+4(2w+2))-4=0



We calculate terms in parentheses: -(2w-3+4(2w+2)), so:

2w-3+4(2w+2)

determiningTheFunctionDomain
2w+4(2w+2)-3

We multiply parentheses

2w+8w+8-3

We add all the numbers together, and all the variables

10w+5

Back to the equation:

-(10w+5)



We get rid of parentheses

-2w-10w-5-4=0

We add all the numbers together, and all the variables

-12w-9=0

We move all terms containing w to the left, all other terms to the right

-12w=9

w=9/-12

w=-3/4

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