-2(w+4)=2w-4+2(5w+6)

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Solution for -2(w+4)=2w-4+2(5w+6) equation: 



-2(w+4)=2w-4+2(5w+6)

We move all terms to the left:

-2(w+4)-(2w-4+2(5w+6))=0

We multiply parentheses

-2w-(2w-4+2(5w+6))-8=0



We calculate terms in parentheses: -(2w-4+2(5w+6)), so:

2w-4+2(5w+6)

determiningTheFunctionDomain
2w+2(5w+6)-4

We multiply parentheses

2w+10w+12-4

We add all the numbers together, and all the variables

12w+8

Back to the equation:

-(12w+8)



We get rid of parentheses

-2w-12w-8-8=0

We add all the numbers together, and all the variables

-14w-16=0

We move all terms containing w to the left, all other terms to the right

-14w=16

w=16/-14

w=-1+1/7

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