-2(w-9)(-w+3)=0

Solution for -2(w-9)(-w+3)=0 equation:

-2(w-9)(-w+3)=0

We add all the numbers together, and all the variables

-2(w-9)(-1w+3)=0

We multiply parentheses ..

-2(-1w^2+3w+9w-27)=0

We multiply parentheses

2w^2-6w-18w+54=0

We add all the numbers together, and all the variables

2w^2-24w+54=0

a = 2; b = -24; c = +54;
Δ = b2-4ac
Δ = -242-4·2·54
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-12}{2*2}=\frac{12}{4}
=3
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+12}{2*2}=\frac{36}{4}
=9
$