-2(x+1)+3(x-2)=4(x-5)

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Solution for -2(x+1)+3(x-2)=4(x-5) equation: 



-2(x+1)+3(x-2)=4(x-5)

We move all terms to the left:

-2(x+1)+3(x-2)-(4(x-5))=0

We multiply parentheses

-2x+3x-(4(x-5))-2-6=0



We calculate terms in parentheses: -(4(x-5)), so:

4(x-5)

We multiply parentheses

4x-20

Back to the equation:

-(4x-20)



We add all the numbers together, and all the variables

x-(4x-20)-8=0

We get rid of parentheses

x-4x+20-8=0

We add all the numbers together, and all the variables

-3x+12=0

We move all terms containing x to the left, all other terms to the right

-3x=-12

x=-12/-3

x=+4

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