-2(x+1)+3(x-2)=4(x-5)

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Solution for -2(x+1)+3(x-2)=4(x-5) equation:



-2(x+1)+3(x-2)=4(x-5)
We move all terms to the left:
-2(x+1)+3(x-2)-(4(x-5))=0
We multiply parentheses
-2x+3x-(4(x-5))-2-6=0
We calculate terms in parentheses: -(4(x-5)), so:
4(x-5)
We multiply parentheses
4x-20
Back to the equation:
-(4x-20)
We add all the numbers together, and all the variables
x-(4x-20)-8=0
We get rid of parentheses
x-4x+20-8=0
We add all the numbers together, and all the variables
-3x+12=0
We move all terms containing x to the left, all other terms to the right
-3x=-12
x=-12/-3
x=+4

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