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-2(x+1)+4(3-x)=(12x-6)/3-6(x-5)
We move all terms to the left:
-2(x+1)+4(3-x)-((12x-6)/3-6(x-5))=0
Domain of the equation: 3-6(x-5))!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
-6(x-5))!=-3
x∈R
-2(x+1)+4(-1x+3)-((12x-6)/3-6(x-5))=0
We multiply parentheses
-2x-4x-((12x-6)/3-6(x-5))-2+12=0
We multiply all the terms by the denominator
-2x*3-6(x-5))-4x*3-6(x-5))-((12x-6)-2*3-6(x-5))+12*3-6(x-5))=0
Wy multiply elements
-6x-6(x-5))-4x*3-6(x-5))-((12x-6)-2*3-6(x-5))+12*3-6(x-5))=0
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