-2(x+1)+4(3-x)=(12x-6)/3-6(x-5))

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Solution for -2(x+1)+4(3-x)=(12x-6)/3-6(x-5)) equation:



-2(x+1)+4(3-x)=(12x-6)/3-6(x-5))
We move all terms to the left:
-2(x+1)+4(3-x)-((12x-6)/3-6(x-5)))=0
Domain of the equation: 3-6(x-5)))!=0
We move all terms containing x to the left, all other terms to the right
-6(x-5)))!=-3
x∈R
We add all the numbers together, and all the variables
-2(x+1)+4(-1x+3)-((12x-6)/3-6(x-5)))=0
We multiply parentheses
-2x-4x-((12x-6)/3-6(x-5)))-2+12=0
We multiply all the terms by the denominator
-2x*3-6(x-5)))-2+12-4x*3-6(x-5)))-2+12-((12x-6)=0
Wy multiply elements
-6x-6(x-5)))-2+12-4x*3-6(x-5)))-2+12-((12x-6)=0

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