-2(x+1)+4(3-x)=(12x-6)3-6(x-5)

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Solution for -2(x+1)+4(3-x)=(12x-6)3-6(x-5) equation:



-2(x+1)+4(3-x)=(12x-6)3-6(x-5)
We move all terms to the left:
-2(x+1)+4(3-x)-((12x-6)3-6(x-5))=0
We add all the numbers together, and all the variables
-2(x+1)+4(-1x+3)-((12x-6)3-6(x-5))=0
We multiply parentheses
-2x-4x-((12x-6)3-6(x-5))-2+12=0
We calculate terms in parentheses: -((12x-6)3-6(x-5)), so:
(12x-6)3-6(x-5)
We multiply parentheses
36x-6x-18+30
We add all the numbers together, and all the variables
30x+12
Back to the equation:
-(30x+12)
We add all the numbers together, and all the variables
-6x-(30x+12)+10=0
We get rid of parentheses
-6x-30x-12+10=0
We add all the numbers together, and all the variables
-36x-2=0
We move all terms containing x to the left, all other terms to the right
-36x=2
x=2/-36
x=-1/18

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