-2(x+1)+4(3-x)=(12x-6)3-6(x-5)

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Solution for -2(x+1)+4(3-x)=(12x-6)3-6(x-5) equation: 



-2(x+1)+4(3-x)=(12x-6)3-6(x-5)

We move all terms to the left:

-2(x+1)+4(3-x)-((12x-6)3-6(x-5))=0

We add all the numbers together, and all the variables

-2(x+1)+4(-1x+3)-((12x-6)3-6(x-5))=0

We multiply parentheses

-2x-4x-((12x-6)3-6(x-5))-2+12=0



We calculate terms in parentheses: -((12x-6)3-6(x-5)), so:

(12x-6)3-6(x-5)

We multiply parentheses

36x-6x-18+30

We add all the numbers together, and all the variables

30x+12

Back to the equation:

-(30x+12)



We add all the numbers together, and all the variables

-6x-(30x+12)+10=0

We get rid of parentheses

-6x-30x-12+10=0

We add all the numbers together, and all the variables

-36x-2=0

We move all terms containing x to the left, all other terms to the right

-36x=2

x=2/-36

x=-1/18

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