-2(x+2)+x=3(x-2)-2

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Solution for -2(x+2)+x=3(x-2)-2 equation:



-2(x+2)+x=3(x-2)-2
We move all terms to the left:
-2(x+2)+x-(3(x-2)-2)=0
We add all the numbers together, and all the variables
x-2(x+2)-(3(x-2)-2)=0
We multiply parentheses
x-2x-(3(x-2)-2)-4=0
We calculate terms in parentheses: -(3(x-2)-2), so:
3(x-2)-2
We multiply parentheses
3x-6-2
We add all the numbers together, and all the variables
3x-8
Back to the equation:
-(3x-8)
We add all the numbers together, and all the variables
-1x-(3x-8)-4=0
We get rid of parentheses
-1x-3x+8-4=0
We add all the numbers together, and all the variables
-4x+4=0
We move all terms containing x to the left, all other terms to the right
-4x=-4
x=-4/-4
x=1

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