-2(x+2)=4x-2+2(6x+3)

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Solution for -2(x+2)=4x-2+2(6x+3) equation: 



-2(x+2)=4x-2+2(6x+3)

We move all terms to the left:

-2(x+2)-(4x-2+2(6x+3))=0

We multiply parentheses

-2x-(4x-2+2(6x+3))-4=0



We calculate terms in parentheses: -(4x-2+2(6x+3)), so:

4x-2+2(6x+3)

determiningTheFunctionDomain
4x+2(6x+3)-2

We multiply parentheses

4x+12x+6-2

We add all the numbers together, and all the variables

16x+4

Back to the equation:

-(16x+4)



We get rid of parentheses

-2x-16x-4-4=0

We add all the numbers together, and all the variables

-18x-8=0

We move all terms containing x to the left, all other terms to the right

-18x=8

x=8/-18

x=-4/9

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