-2(x+2)=6x-8+5(2x+4)

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Solution for -2(x+2)=6x-8+5(2x+4) equation: 



-2(x+2)=6x-8+5(2x+4)

We move all terms to the left:

-2(x+2)-(6x-8+5(2x+4))=0

We multiply parentheses

-2x-(6x-8+5(2x+4))-4=0



We calculate terms in parentheses: -(6x-8+5(2x+4)), so:

6x-8+5(2x+4)

determiningTheFunctionDomain
6x+5(2x+4)-8

We multiply parentheses

6x+10x+20-8

We add all the numbers together, and all the variables

16x+12

Back to the equation:

-(16x+12)



We get rid of parentheses

-2x-16x-12-4=0

We add all the numbers together, and all the variables

-18x-16=0

We move all terms containing x to the left, all other terms to the right

-18x=16

x=16/-18

x=-8/9

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