-2(x+3)-4=3x+2(1-x)

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Solution for -2(x+3)-4=3x+2(1-x) equation: 



-2(x+3)-4=3x+2(1-x)

We move all terms to the left:

-2(x+3)-4-(3x+2(1-x))=0

We add all the numbers together, and all the variables

-2(x+3)-(3x+2(-1x+1))-4=0

We multiply parentheses

-2x-(3x+2(-1x+1))-6-4=0



We calculate terms in parentheses: -(3x+2(-1x+1)), so:

3x+2(-1x+1)

We multiply parentheses

3x-2x+2

We add all the numbers together, and all the variables

x+2

Back to the equation:

-(x+2)



We add all the numbers together, and all the variables

-2x-(x+2)-10=0

We get rid of parentheses

-2x-x-2-10=0

We add all the numbers together, and all the variables

-3x-12=0

We move all terms containing x to the left, all other terms to the right

-3x=12

x=12/-3

x=-4

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