-2(x+3)-6(2x-4)+108=0

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Solution for -2(x+3)-6(2x-4)+108=0 equation:


Simplifying
-2(x + 3) + -6(2x + -4) + 108 = 0

Reorder the terms:
-2(3 + x) + -6(2x + -4) + 108 = 0
(3 * -2 + x * -2) + -6(2x + -4) + 108 = 0
(-6 + -2x) + -6(2x + -4) + 108 = 0

Reorder the terms:
-6 + -2x + -6(-4 + 2x) + 108 = 0
-6 + -2x + (-4 * -6 + 2x * -6) + 108 = 0
-6 + -2x + (24 + -12x) + 108 = 0

Reorder the terms:
-6 + 24 + 108 + -2x + -12x = 0

Combine like terms: -6 + 24 = 18
18 + 108 + -2x + -12x = 0

Combine like terms: 18 + 108 = 126
126 + -2x + -12x = 0

Combine like terms: -2x + -12x = -14x
126 + -14x = 0

Solving
126 + -14x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-126' to each side of the equation.
126 + -126 + -14x = 0 + -126

Combine like terms: 126 + -126 = 0
0 + -14x = 0 + -126
-14x = 0 + -126

Combine like terms: 0 + -126 = -126
-14x = -126

Divide each side by '-14'.
x = 9

Simplifying
x = 9

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