-2(x+4)(x-1)-(-2x-3)(x-1)=0

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Solution for -2(x+4)(x-1)-(-2x-3)(x-1)=0 equation:



-2(x+4)(x-1)-(-2x-3)(x-1)=0
We multiply parentheses ..
-2(+x^2-1x+4x-4)-(-2x-3)(x-1)=0
We multiply parentheses
-2x^2+2x-8x-(-2x-3)(x-1)+8=0
We multiply parentheses ..
-2x^2-(-2x^2+2x-3x+3)+2x-8x+8=0
We add all the numbers together, and all the variables
-2x^2-(-2x^2+2x-3x+3)-6x+8=0
We get rid of parentheses
-2x^2+2x^2-2x+3x-6x-3+8=0
We add all the numbers together, and all the variables
-5x+5=0
We move all terms containing x to the left, all other terms to the right
-5x=-5
x=-5/-5
x=1

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