-2(x+4)=3(x-2)+8

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Solution for -2(x+4)=3(x-2)+8 equation: 



-2(x+4)=3(x-2)+8

We move all terms to the left:

-2(x+4)-(3(x-2)+8)=0

We multiply parentheses

-2x-(3(x-2)+8)-8=0



We calculate terms in parentheses: -(3(x-2)+8), so:

3(x-2)+8

We multiply parentheses

3x-6+8

We add all the numbers together, and all the variables

3x+2

Back to the equation:

-(3x+2)



We get rid of parentheses

-2x-3x-2-8=0

We add all the numbers together, and all the variables

-5x-10=0

We move all terms containing x to the left, all other terms to the right

-5x=10

x=10/-5

x=-2

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