-2(x+6)+3(2x-3)=2(x+2)-8

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Solution for -2(x+6)+3(2x-3)=2(x+2)-8 equation: 



-2(x+6)+3(2x-3)=2(x+2)-8

We move all terms to the left:

-2(x+6)+3(2x-3)-(2(x+2)-8)=0

We multiply parentheses

-2x+6x-(2(x+2)-8)-12-9=0



We calculate terms in parentheses: -(2(x+2)-8), so:

2(x+2)-8

We multiply parentheses

2x+4-8

We add all the numbers together, and all the variables

2x-4

Back to the equation:

-(2x-4)



We add all the numbers together, and all the variables

4x-(2x-4)-21=0

We get rid of parentheses

4x-2x+4-21=0

We add all the numbers together, and all the variables

2x-17=0

We move all terms containing x to the left, all other terms to the right

2x=17

x=17/2

x=8+1/2

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