-2(x+6)+3(2x-5)=3(x+4)+10

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Solution for -2(x+6)+3(2x-5)=3(x+4)+10 equation: 



-2(x+6)+3(2x-5)=3(x+4)+10

We move all terms to the left:

-2(x+6)+3(2x-5)-(3(x+4)+10)=0

We multiply parentheses

-2x+6x-(3(x+4)+10)-12-15=0



We calculate terms in parentheses: -(3(x+4)+10), so:

3(x+4)+10

We multiply parentheses

3x+12+10

We add all the numbers together, and all the variables

3x+22

Back to the equation:

-(3x+22)



We add all the numbers together, and all the variables

4x-(3x+22)-27=0

We get rid of parentheses

4x-3x-22-27=0

We add all the numbers together, and all the variables

x-49=0

We move all terms containing x to the left, all other terms to the right

x=49

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