-2(x-2)-3=3(x-4)+20

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Solution for -2(x-2)-3=3(x-4)+20 equation: 



-2(x-2)-3=3(x-4)+20

We move all terms to the left:

-2(x-2)-3-(3(x-4)+20)=0

We multiply parentheses

-2x-(3(x-4)+20)+4-3=0



We calculate terms in parentheses: -(3(x-4)+20), so:

3(x-4)+20

We multiply parentheses

3x-12+20

We add all the numbers together, and all the variables

3x+8

Back to the equation:

-(3x+8)



We add all the numbers together, and all the variables

-2x-(3x+8)+1=0

We get rid of parentheses

-2x-3x-8+1=0

We add all the numbers together, and all the variables

-5x-7=0

We move all terms containing x to the left, all other terms to the right

-5x=7

x=7/-5

x=-1+2/5

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