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-2(x-3)-8=-3(x+2)
We move all terms to the left:
-2(x-3)-8-(-3(x+2))=0
We multiply parentheses
-2x-(-3(x+2))+6-8=0
We calculate terms in parentheses: -(-3(x+2)), so:We add all the numbers together, and all the variables
-3(x+2)
We multiply parentheses
-3x-6
Back to the equation:
-(-3x-6)
-2x-(-3x-6)-2=0
We get rid of parentheses
-2x+3x+6-2=0
We add all the numbers together, and all the variables
x+4=0
We move all terms containing x to the left, all other terms to the right
x=-4
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