-2(x-4)(4-x)=0

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Solution for -2(x-4)(4-x)=0 equation: 



-2(x-4)(4-x)=0

We add all the numbers together, and all the variables

-2(x-4)(-1x+4)=0

We multiply parentheses ..

-2(-1x^2+4x+4x-16)=0

We multiply parentheses

2x^2-8x-8x+32=0

We add all the numbers together, and all the variables

2x^2-16x+32=0

a = 2; b = -16; c = +32;
Δ = b2-4ac
Δ = -162-4·2·32
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{16}{4}=4$

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