-2(x-4)+2=3(2x-4)+3x

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Solution for -2(x-4)+2=3(2x-4)+3x equation: 



-2(x-4)+2=3(2x-4)+3x

We move all terms to the left:

-2(x-4)+2-(3(2x-4)+3x)=0

We multiply parentheses

-2x-(3(2x-4)+3x)+8+2=0



We calculate terms in parentheses: -(3(2x-4)+3x), so:

3(2x-4)+3x

We add all the numbers together, and all the variables

3x+3(2x-4)

We multiply parentheses

3x+6x-12

We add all the numbers together, and all the variables

9x-12

Back to the equation:

-(9x-12)



We add all the numbers together, and all the variables

-2x-(9x-12)+10=0

We get rid of parentheses

-2x-9x+12+10=0

We add all the numbers together, and all the variables

-11x+22=0

We move all terms containing x to the left, all other terms to the right

-11x=-22

x=-22/-11

x=+2

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