-2(x-4)+3x=-(x+6)+8

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Solution for -2(x-4)+3x=-(x+6)+8 equation: 



-2(x-4)+3x=-(x+6)+8

We move all terms to the left:

-2(x-4)+3x-(-(x+6)+8)=0

We add all the numbers together, and all the variables

3x-2(x-4)-(-(x+6)+8)=0

We multiply parentheses

3x-2x-(-(x+6)+8)+8=0



We calculate terms in parentheses: -(-(x+6)+8), so:

-(x+6)+8

We get rid of parentheses

-x-6+8

We add all the numbers together, and all the variables

-1x+2

Back to the equation:

-(-1x+2)



We add all the numbers together, and all the variables

x-(-1x+2)+8=0

We get rid of parentheses

x+1x-2+8=0

We add all the numbers together, and all the variables

2x+6=0

We move all terms containing x to the left, all other terms to the right

2x=-6

x=-6/2

x=-3

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