-2(x-4)+3x=2(x+4)-x

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Solution for -2(x-4)+3x=2(x+4)-x equation: 



-2(x-4)+3x=2(x+4)-x

We move all terms to the left:

-2(x-4)+3x-(2(x+4)-x)=0

We add all the numbers together, and all the variables

3x-2(x-4)-(2(x+4)-x)=0

We multiply parentheses

3x-2x-(2(x+4)-x)+8=0



We calculate terms in parentheses: -(2(x+4)-x), so:

2(x+4)-x

We add all the numbers together, and all the variables

-1x+2(x+4)

We multiply parentheses

-1x+2x+8

We add all the numbers together, and all the variables

x+8

Back to the equation:

-(x+8)



We add all the numbers together, and all the variables

x-(x+8)+8=0

We get rid of parentheses

x-x-8+8=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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