-2(x-4)+4=3(x-4)+3x

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Solution for -2(x-4)+4=3(x-4)+3x equation: 



-2(x-4)+4=3(x-4)+3x

We move all terms to the left:

-2(x-4)+4-(3(x-4)+3x)=0

We multiply parentheses

-2x-(3(x-4)+3x)+8+4=0



We calculate terms in parentheses: -(3(x-4)+3x), so:

3(x-4)+3x

We add all the numbers together, and all the variables

3x+3(x-4)

We multiply parentheses

3x+3x-12

We add all the numbers together, and all the variables

6x-12

Back to the equation:

-(6x-12)



We add all the numbers together, and all the variables

-2x-(6x-12)+12=0

We get rid of parentheses

-2x-6x+12+12=0

We add all the numbers together, and all the variables

-8x+24=0

We move all terms containing x to the left, all other terms to the right

-8x=-24

x=-24/-8

x=+3

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