-2(x-4)=3(-2x+12)

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Solution for -2(x-4)=3(-2x+12) equation: 



-2(x-4)=3(-2x+12)

We move all terms to the left:

-2(x-4)-(3(-2x+12))=0

We multiply parentheses

-2x-(3(-2x+12))+8=0



We calculate terms in parentheses: -(3(-2x+12)), so:

3(-2x+12)

We multiply parentheses

-6x+36

Back to the equation:

-(-6x+36)



We get rid of parentheses

-2x+6x-36+8=0

We add all the numbers together, and all the variables

4x-28=0

We move all terms containing x to the left, all other terms to the right

4x=28

x=28/4

x=7

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