-2(x-5)-8=2(x+3)

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Solution for -2(x-5)-8=2(x+3) equation: 



-2(x-5)-8=2(x+3)

We move all terms to the left:

-2(x-5)-8-(2(x+3))=0

We multiply parentheses

-2x-(2(x+3))+10-8=0



We calculate terms in parentheses: -(2(x+3)), so:

2(x+3)

We multiply parentheses

2x+6

Back to the equation:

-(2x+6)



We add all the numbers together, and all the variables

-2x-(2x+6)+2=0

We get rid of parentheses

-2x-2x-6+2=0

We add all the numbers together, and all the variables

-4x-4=0

We move all terms containing x to the left, all other terms to the right

-4x=4

x=4/-4

x=-1

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