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-2(x-5)=-(2x+2)
We move all terms to the left:
-2(x-5)-(-(2x+2))=0
We multiply parentheses
-2x-(-(2x+2))+10=0
We calculate terms in parentheses: -(-(2x+2)), so:We get rid of parentheses
-(2x+2)
We get rid of parentheses
-2x-2
Back to the equation:
-(-2x-2)
-2x+2x+2+10=0
We add all the numbers together, and all the variables
12!=0
There is no solution for this equation
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