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-2(x-5)=3(4-x)
We move all terms to the left:
-2(x-5)-(3(4-x))=0
We add all the numbers together, and all the variables
-2(x-5)-(3(-1x+4))=0
We multiply parentheses
-2x-(3(-1x+4))+10=0
We calculate terms in parentheses: -(3(-1x+4)), so:We get rid of parentheses
3(-1x+4)
We multiply parentheses
-3x+12
Back to the equation:
-(-3x+12)
-2x+3x-12+10=0
We add all the numbers together, and all the variables
x-2=0
We move all terms containing x to the left, all other terms to the right
x=2
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