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-2(x-5)=3(x+4)-2
We move all terms to the left:
-2(x-5)-(3(x+4)-2)=0
We multiply parentheses
-2x-(3(x+4)-2)+10=0
We calculate terms in parentheses: -(3(x+4)-2), so:We get rid of parentheses
3(x+4)-2
We multiply parentheses
3x+12-2
We add all the numbers together, and all the variables
3x+10
Back to the equation:
-(3x+10)
-2x-3x-10+10=0
We add all the numbers together, and all the variables
-5x=0
x=0/-5
x=0
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