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-2(x-5)=3x-(3x+2)
We move all terms to the left:
-2(x-5)-(3x-(3x+2))=0
We multiply parentheses
-2x-(3x-(3x+2))+10=0
We calculate terms in parentheses: -(3x-(3x+2)), so:We add all the numbers together, and all the variables
3x-(3x+2)
We get rid of parentheses
3x-3x-2
We add all the numbers together, and all the variables
-2
Back to the equation:
-(-2)
-2x+12=0
We move all terms containing x to the left, all other terms to the right
-2x=-12
x=-12/-2
x=+6
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