-2(x6)+3(2x-5)=3(x-4)+10

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Solution for -2(x6)+3(2x-5)=3(x-4)+10 equation: 



-2(x6)+3(2x-5)=3(x-4)+10

We move all terms to the left:

-2(x6)+3(2x-5)-(3(x-4)+10)=0

We add all the numbers together, and all the variables

-2x^6+3(2x-5)-(3(x-4)+10)=0

We multiply parentheses

-2x^6+6x-(3(x-4)+10)-15=0



We calculate terms in parentheses: -(3(x-4)+10), so:

3(x-4)+10

We multiply parentheses

3x-12+10

We add all the numbers together, and all the variables

3x-2

Back to the equation:

-(3x-2)



We do not support expression: x^6

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