-2(y+1)+5y=3(y+1)-2

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Solution for -2(y+1)+5y=3(y+1)-2 equation: 


Simplifying
-2(y + 1) + 5y = 3(y + 1) + -2

Reorder the terms:
-2(1 + y) + 5y = 3(y + 1) + -2
(1 * -2 + y * -2) + 5y = 3(y + 1) + -2
(-2 + -2y) + 5y = 3(y + 1) + -2

Combine like terms: -2y + 5y = 3y
-2 + 3y = 3(y + 1) + -2

Reorder the terms:
-2 + 3y = 3(1 + y) + -2
-2 + 3y = (1 * 3 + y * 3) + -2
-2 + 3y = (3 + 3y) + -2

Reorder the terms:
-2 + 3y = 3 + -2 + 3y

Combine like terms: 3 + -2 = 1
-2 + 3y = 1 + 3y

Add '-3y' to each side of the equation.
-2 + 3y + -3y = 1 + 3y + -3y

Combine like terms: 3y + -3y = 0
-2 + 0 = 1 + 3y + -3y
-2 = 1 + 3y + -3y

Combine like terms: 3y + -3y = 0
-2 = 1 + 0
-2 = 1

Solving
-2 = 1

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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