-2(y+1)=2y-2+2(5y+9)

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Solution for -2(y+1)=2y-2+2(5y+9) equation: 



-2(y+1)=2y-2+2(5y+9)

We move all terms to the left:

-2(y+1)-(2y-2+2(5y+9))=0

We multiply parentheses

-2y-(2y-2+2(5y+9))-2=0



We calculate terms in parentheses: -(2y-2+2(5y+9)), so:

2y-2+2(5y+9)

determiningTheFunctionDomain
2y+2(5y+9)-2

We multiply parentheses

2y+10y+18-2

We add all the numbers together, and all the variables

12y+16

Back to the equation:

-(12y+16)



We get rid of parentheses

-2y-12y-16-2=0

We add all the numbers together, and all the variables

-14y-18=0

We move all terms containing y to the left, all other terms to the right

-14y=18

y=18/-14

y=-1+2/7

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