-2(y+1)=4y-5+3(4y+3)

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Solution for -2(y+1)=4y-5+3(4y+3) equation: 



-2(y+1)=4y-5+3(4y+3)

We move all terms to the left:

-2(y+1)-(4y-5+3(4y+3))=0

We multiply parentheses

-2y-(4y-5+3(4y+3))-2=0



We calculate terms in parentheses: -(4y-5+3(4y+3)), so:

4y-5+3(4y+3)

determiningTheFunctionDomain
4y+3(4y+3)-5

We multiply parentheses

4y+12y+9-5

We add all the numbers together, and all the variables

16y+4

Back to the equation:

-(16y+4)



We get rid of parentheses

-2y-16y-4-2=0

We add all the numbers together, and all the variables

-18y-6=0

We move all terms containing y to the left, all other terms to the right

-18y=6

y=6/-18

y=-1/3

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