-2(y+1)=y-3+2(3y+2)

Solution for -2(y+1)=y-3+2(3y+2) equation:

-2(y+1)=y-3+2(3y+2)

We move all terms to the left:

-2(y+1)-(y-3+2(3y+2))=0

We multiply parentheses

-2y-(y-3+2(3y+2))-2=0


We calculate terms in parentheses: -(y-3+2(3y+2)), so:

y-3+2(3y+2)

determiningTheFunctionDomain
y+2(3y+2)-3

We multiply parentheses

y+6y+4-3

We add all the numbers together, and all the variables

7y+1

Back to the equation:

-(7y+1)


We get rid of parentheses

-2y-7y-1-2=0

We add all the numbers together, and all the variables

-9y-3=0

We move all terms containing y to the left, all other terms to the right

-9y=3

y=3/-9

y=-1/3