-2(y+2)+11=4(y+5)+2y+19

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Solution for -2(y+2)+11=4(y+5)+2y+19 equation: 



-2(y+2)+11=4(y+5)+2y+19

We move all terms to the left:

-2(y+2)+11-(4(y+5)+2y+19)=0

We multiply parentheses

-2y-(4(y+5)+2y+19)-4+11=0



We calculate terms in parentheses: -(4(y+5)+2y+19), so:

4(y+5)+2y+19

We add all the numbers together, and all the variables

2y+4(y+5)+19

We multiply parentheses

2y+4y+20+19

We add all the numbers together, and all the variables

6y+39

Back to the equation:

-(6y+39)



We add all the numbers together, and all the variables

-2y-(6y+39)+7=0

We get rid of parentheses

-2y-6y-39+7=0

We add all the numbers together, and all the variables

-8y-32=0

We move all terms containing y to the left, all other terms to the right

-8y=32

y=32/-8

y=-4

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