-2(y+2)+3(3y+3)=-2y-4+9y+9

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Solution for -2(y+2)+3(3y+3)=-2y-4+9y+9 equation: 



-2(y+2)+3(3y+3)=-2y-4+9y+9

We move all terms to the left:

-2(y+2)+3(3y+3)-(-2y-4+9y+9)=0

We add all the numbers together, and all the variables

-2(y+2)+3(3y+3)-(7y+5)=0

We multiply parentheses

-2y+9y-(7y+5)-4+9=0

We get rid of parentheses

-2y+9y-7y-5-4+9=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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