-2(y+2)+3(3y+3)=-2y-4+9y+9

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Solution for -2(y+2)+3(3y+3)=-2y-4+9y+9 equation:



-2(y+2)+3(3y+3)=-2y-4+9y+9
We move all terms to the left:
-2(y+2)+3(3y+3)-(-2y-4+9y+9)=0
We add all the numbers together, and all the variables
-2(y+2)+3(3y+3)-(7y+5)=0
We multiply parentheses
-2y+9y-(7y+5)-4+9=0
We get rid of parentheses
-2y+9y-7y-5-4+9=0
We add all the numbers together, and all the variables
=0
y=0/1
y=0

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