-2(y+2)=4y-6+4(3y+1)

Solution for -2(y+2)=4y-6+4(3y+1) equation:

-2(y+2)=4y-6+4(3y+1)

We move all terms to the left:

-2(y+2)-(4y-6+4(3y+1))=0

We multiply parentheses

-2y-(4y-6+4(3y+1))-4=0


We calculate terms in parentheses: -(4y-6+4(3y+1)), so:

4y-6+4(3y+1)

determiningTheFunctionDomain
4y+4(3y+1)-6

We multiply parentheses

4y+12y+4-6

We add all the numbers together, and all the variables

16y-2

Back to the equation:

-(16y-2)


We get rid of parentheses

-2y-16y+2-4=0

We add all the numbers together, and all the variables

-18y-2=0

We move all terms containing y to the left, all other terms to the right

-18y=2

y=2/-18

y=-1/9