-2(y+2)=4y-6+4(3y+1)

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Solution for -2(y+2)=4y-6+4(3y+1) equation:



-2(y+2)=4y-6+4(3y+1)
We move all terms to the left:
-2(y+2)-(4y-6+4(3y+1))=0
We multiply parentheses
-2y-(4y-6+4(3y+1))-4=0
We calculate terms in parentheses: -(4y-6+4(3y+1)), so:
4y-6+4(3y+1)
determiningTheFunctionDomain 4y+4(3y+1)-6
We multiply parentheses
4y+12y+4-6
We add all the numbers together, and all the variables
16y-2
Back to the equation:
-(16y-2)
We get rid of parentheses
-2y-16y+2-4=0
We add all the numbers together, and all the variables
-18y-2=0
We move all terms containing y to the left, all other terms to the right
-18y=2
y=2/-18
y=-1/9

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