-2(y+2)=4y-7+2(6y+6)

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Solution for -2(y+2)=4y-7+2(6y+6) equation: 



-2(y+2)=4y-7+2(6y+6)

We move all terms to the left:

-2(y+2)-(4y-7+2(6y+6))=0

We multiply parentheses

-2y-(4y-7+2(6y+6))-4=0



We calculate terms in parentheses: -(4y-7+2(6y+6)), so:

4y-7+2(6y+6)

determiningTheFunctionDomain
4y+2(6y+6)-7

We multiply parentheses

4y+12y+12-7

We add all the numbers together, and all the variables

16y+5

Back to the equation:

-(16y+5)



We get rid of parentheses

-2y-16y-5-4=0

We add all the numbers together, and all the variables

-18y-9=0

We move all terms containing y to the left, all other terms to the right

-18y=9

y=9/-18

y=-1/2

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