-2(y+2)=7y-9+3(2y+5)

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Solution for -2(y+2)=7y-9+3(2y+5) equation:



-2(y+2)=7y-9+3(2y+5)
We move all terms to the left:
-2(y+2)-(7y-9+3(2y+5))=0
We multiply parentheses
-2y-(7y-9+3(2y+5))-4=0
We calculate terms in parentheses: -(7y-9+3(2y+5)), so:
7y-9+3(2y+5)
determiningTheFunctionDomain 7y+3(2y+5)-9
We multiply parentheses
7y+6y+15-9
We add all the numbers together, and all the variables
13y+6
Back to the equation:
-(13y+6)
We get rid of parentheses
-2y-13y-6-4=0
We add all the numbers together, and all the variables
-15y-10=0
We move all terms containing y to the left, all other terms to the right
-15y=10
y=10/-15
y=-2/3

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