-2(y+2)=7y-9+3(2y+5)

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Solution for -2(y+2)=7y-9+3(2y+5) equation: 



-2(y+2)=7y-9+3(2y+5)

We move all terms to the left:

-2(y+2)-(7y-9+3(2y+5))=0

We multiply parentheses

-2y-(7y-9+3(2y+5))-4=0



We calculate terms in parentheses: -(7y-9+3(2y+5)), so:

7y-9+3(2y+5)

determiningTheFunctionDomain
7y+3(2y+5)-9

We multiply parentheses

7y+6y+15-9

We add all the numbers together, and all the variables

13y+6

Back to the equation:

-(13y+6)



We get rid of parentheses

-2y-13y-6-4=0

We add all the numbers together, and all the variables

-15y-10=0

We move all terms containing y to the left, all other terms to the right

-15y=10

y=10/-15

y=-2/3

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