-2(y+2)=8y-8+2(3y+3)

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Solution for -2(y+2)=8y-8+2(3y+3) equation: 



-2(y+2)=8y-8+2(3y+3)

We move all terms to the left:

-2(y+2)-(8y-8+2(3y+3))=0

We multiply parentheses

-2y-(8y-8+2(3y+3))-4=0



We calculate terms in parentheses: -(8y-8+2(3y+3)), so:

8y-8+2(3y+3)

determiningTheFunctionDomain
8y+2(3y+3)-8

We multiply parentheses

8y+6y+6-8

We add all the numbers together, and all the variables

14y-2

Back to the equation:

-(14y-2)



We get rid of parentheses

-2y-14y+2-4=0

We add all the numbers together, and all the variables

-16y-2=0

We move all terms containing y to the left, all other terms to the right

-16y=2

y=2/-16

y=-1/8

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