-2(y+2)=y-7+2(6y+3)

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Solution for -2(y+2)=y-7+2(6y+3) equation: 



-2(y+2)=y-7+2(6y+3)

We move all terms to the left:

-2(y+2)-(y-7+2(6y+3))=0

We multiply parentheses

-2y-(y-7+2(6y+3))-4=0



We calculate terms in parentheses: -(y-7+2(6y+3)), so:

y-7+2(6y+3)

determiningTheFunctionDomain
y+2(6y+3)-7

We multiply parentheses

y+12y+6-7

We add all the numbers together, and all the variables

13y-1

Back to the equation:

-(13y-1)



We get rid of parentheses

-2y-13y+1-4=0

We add all the numbers together, and all the variables

-15y-3=0

We move all terms containing y to the left, all other terms to the right

-15y=3

y=3/-15

y=-1/5

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