-2(y+3)=-3(7y-4)+5y

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Solution for -2(y+3)=-3(7y-4)+5y equation: 



-2(y+3)=-3(7y-4)+5y

We move all terms to the left:

-2(y+3)-(-3(7y-4)+5y)=0

We multiply parentheses

-2y-(-3(7y-4)+5y)-6=0



We calculate terms in parentheses: -(-3(7y-4)+5y), so:

-3(7y-4)+5y

We add all the numbers together, and all the variables

5y-3(7y-4)

We multiply parentheses

5y-21y+12

We add all the numbers together, and all the variables

-16y+12

Back to the equation:

-(-16y+12)



We get rid of parentheses

-2y+16y-12-6=0

We add all the numbers together, and all the variables

14y-18=0

We move all terms containing y to the left, all other terms to the right

14y=18

y=18/14

y=1+2/7

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