-2(y+3)=2y-8+2(4y+8)

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Solution for -2(y+3)=2y-8+2(4y+8) equation: 



-2(y+3)=2y-8+2(4y+8)

We move all terms to the left:

-2(y+3)-(2y-8+2(4y+8))=0

We multiply parentheses

-2y-(2y-8+2(4y+8))-6=0



We calculate terms in parentheses: -(2y-8+2(4y+8)), so:

2y-8+2(4y+8)

determiningTheFunctionDomain
2y+2(4y+8)-8

We multiply parentheses

2y+8y+16-8

We add all the numbers together, and all the variables

10y+8

Back to the equation:

-(10y+8)



We get rid of parentheses

-2y-10y-8-6=0

We add all the numbers together, and all the variables

-12y-14=0

We move all terms containing y to the left, all other terms to the right

-12y=14

y=14/-12

y=-1+1/6

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